x^2+4x+53=0

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Solution for x^2+4x+53=0 equation:


Simplifying
x2 + 4x + 53 = 0

Reorder the terms:
53 + 4x + x2 = 0

Solving
53 + 4x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-53' to each side of the equation.
53 + 4x + -53 + x2 = 0 + -53

Reorder the terms:
53 + -53 + 4x + x2 = 0 + -53

Combine like terms: 53 + -53 = 0
0 + 4x + x2 = 0 + -53
4x + x2 = 0 + -53

Combine like terms: 0 + -53 = -53
4x + x2 = -53

The x term is 4x.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4x + 4 + x2 = -53 + 4

Reorder the terms:
4 + 4x + x2 = -53 + 4

Combine like terms: -53 + 4 = -49
4 + 4x + x2 = -49

Factor a perfect square on the left side:
(x + 2)(x + 2) = -49

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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